Question

Find p(0), p(1) and p(2) for each of the following polynomials:
(iii) p(x) = x^3
(iv) p(x) = (x – 1) (x + 1)​

Answer 1

Step-by-step explanation:

1. p(x)=x³

p(0)=0³

p(0)=0

p(1)=1³

p(1)=1

p(2)=2³

p(2)=8

2. in polynomial (x-1)(x+1)

=x²-1²

p(0)=0²-1²

=-1

p(1)=1²-1²

=0

p(2)=2²-1²

=4-1

=3

hope this helps you

Answer 2

Answer:

1)

p(0)=0

p(1)=1

p(2)=8

2) [x^2-1^2]

p(0)=-1

p(1)=0

p(2)=3

Hope it helps