Question

Find p(0), p(1) and p(2) for each of the following polynomials: (i) p(y) = y 2 − y + 1 (ii) p(t) = 2 + t + 2t 2 − t 3 (iii) p(x) = x 3 (iv) p(x) = (x − 1) (x + 1)

Answer 1

Answer of the question

Answer 2

Hey Dear,

(i) p(y) = y^2 − y + 1

p(0) = 0^2 − 0 + 1 = 1

p(1) = 1^2 − 1 + 1 = 1

p(2) = 2^2 − 2 + 1 = 3

(ii) p(t) = 2 + t + 2t

p(0) = 2 + 0 + 2×0 = 2

p(1) = 2 + 1 + 2×1 = 5

p(2) = 2 + 2 + 2×2 = 8

(iii) p(x) = x^3

p(0) = 0^3 = 0

p(1) = 1^3 = 1

p(2) = 2^3 = 8

(iv) p(x) = (x−1) (x+1)

p(0) = (0−1) (0+1) = -1

p(1) = (1−1) (1+1) = 0

p(2) = (2−1) (2+1) = 3

Best luck dear..