Question

Find p(0),p(1),and p(2) for each of the following polynomials ....

i)p(y)=y^2-y+1

ii)p(t)=2+t+2t^2-t^3​

Answer 1

Step-by-step explanation:

• p(y) =y^2-y+1

=> p(0) =0^2-0+1

=> p(0) =0-0+1

=> p(0) = 1

• p(1) = 1^2-1+1

=> p(1) =1-1+1

=> p(1) =1

• p(2) =2^2-2+1

=> p(2) = 4-2+1

=> p(2) = 5-2

=> p(2) = 3

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Answer 2

Answer:

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