Find p(0) , p(1) and p(2) for p(x) = 4x²+x-5
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at p(0)= 4 × 0 + 0 - 5
= - 5
at p(1)= 4 × 1 + 1 - 5
= 0
at p(2) = 4 × 4 + 2 - 5
= 13
= - 5
at p(1)= 4 × 1 + 1 - 5
= 0
at p(2) = 4 × 4 + 2 - 5
= 13
Anonymous:
hope i help you
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