find p(0) p(1) and p(2) for p(y) 2+y +2y2_ y3
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Given polynomial is p(y) => 2 + y + 2y² - y²
Replace y by 0 , we get
p(0) => 2 +
⇒p(0)=2+0+0+0
⇒p(0)=2
Replace y by 1, we get
p(1)=2+1+2(1)
2
−(1)
3
⇒p(1)=2+1+2−1
⇒p(1)=4
Replace y by 2, we get
p(2)=2+2+2(2)
2
−(2)
3
⇒p(2)=2+2+8−8
⇒p(2)=4
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