Question

find p(0) p(1) and p(3) for p(t) = (t-1) (t+1)

Answer 1

Heya !!




P(T) = ( T - 1 ) ( T + 1 )




=> T² - 1





P(0) = (0)² - 1


=> -1




P(1) = (1)² - 1


=> 0


P(3) = (3)² - 1


=> 9-1

=> 8.



Hence,



P(0) = -1 , P(1) = 0 and P(3) = 8.