Question

Find P(0), P(-1) for P(x)=

2x^3-2x^2+4x-5.​

Answer 1

Answer:

P(0) = -5,  P(-1) = -13

Step-by-step explanation:

Given : P(x) = 2x^3-2x^2+4x-5

For finding the value of P(0), P(-1). We just have to put 0 and -1 in place of x.

P(0)= substitute x by 0 in P(x) = 2x^3-2x^2+4x-5

∴ P(0) = 2(0)^2-2(0)^2+4(0)-5

          = 0 - 0 + 0 - 5

          = -5

P(-1)= substitute x by -1 in P(x) = 2x^3-2x^2+4x-5

∴ P(-1) = 2(-1)^2-2(-1)^2+4(-1)-5

          = 2(-1) - 2(1) + 4(-1) -5

          = - 2 - 2 - 4 - 5

          = - 13

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