find p(0) p (1) p(2) and each of the following polynomials.p (t)=2+t+2t -t
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FIRST
p(0) =2 + 0+ 2 (0)- 0
= 2+2
= 4
SECOND
p (1) = 2 + 1+2 (1) - 1
= 3 + 2-1
= 4-1
= 3
THIRD
p (2) = 2 + 2 + 2 (2) -2
= 4 +4-2
= 8 - 2
= 6
HOPE ITS HELPFULL FOR U
p(0) =2 + 0+ 2 (0)- 0
= 2+2
= 4
SECOND
p (1) = 2 + 1+2 (1) - 1
= 3 + 2-1
= 4-1
= 3
THIRD
p (2) = 2 + 2 + 2 (2) -2
= 4 +4-2
= 8 - 2
= 6
HOPE ITS HELPFULL FOR U
harpreet6663gimal:
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