Question

find p(0), p(1), p(2) for polynomial p(t)=2+t-2t^2-t^3​

Answer 1

$\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>$

$p(t)=2+t-2t^2-t^3$

So

$p(0)=2+0-2 \times (0)^2-(0)^3 = 2$

$p(1)=2+1-2 \times 1^2-1^3 = 0$

$p(2)=2+2-2 \times 2^2-2^3 = - 12$

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