Question

find p(0), p(1), p(2)for polynomial p(x)=x^3​

Answer 1

Step-by-step explanation:

p(x)=x³

p(0)=(0)³=0

p(1)=(1)³=1

p(2)=(2)³=8

Answer 2

Answer:

$p(x) = {(x)}^{3}$

$p(0) = {(0)}^{3} = 0$

$p(1) = {(1)}^{3} = 1$

$p(2) = {(2)}^{3} = 8$