Math, asked by kourj371, 8 months ago

Find P(0) P(1) P(2) P(3) in P(x) = x²-x+1​

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Answered by Anonymous
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Answered by Anonymous
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p(x) =x²-x+1

Find :- p(0), p(1), p(2), p(3)

Solution:-

p(0) = 0²-0+1 =0+1 = 1

p(1) = 1²-1+1 = 0+1 =1

p(2) = 2²-2+1= 2+1 = 3

p(3) =3²-3+1 = 9-2 =7

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