Question

find p(1/2) p(z) = z^4-z^2+z

Answer 1

Pic have the solution

Answer 2

Given: The given expression is $p(z)=z^4-z^2+z$.

To find: We have to find the value of the expression for p(1/2).

Solution:

To determine the value of the above expression for p(1/2) we have to follow the below steps as follows-

The given expression is $p(z)=z^4-z^2+z$.

For p(1/2) the value of z is 1/2.

Putting the value of z as 1/2 in the above expression we get-

$p( \frac{1}{2} ) = { \frac{1}{2} }^{4} - { \frac{1}{2} }^{2} + \frac{1}{2} \\ p( \frac{1}{2} ) = \frac{1}{16} - \frac{1}{4} + \frac{1}{2} \\ p( \frac{1}{2} ) = \frac{1 - 4 + 8}{16} \\ p( \frac{1}{2} ) = \frac{5}{16}$

The result is 5/16.

The value of the above expression for p(1/2) is 5/16.