Question

find P(1/4),if P(x) =12x^2-7x+1​

Answer 1

Step-by-step explanation:

If x = 1/4,

p(x) = 12x² - 7x + 1

$p( \frac{1}{4} ) = 12 ({ \frac{1}{4} }^{2}) - 7( \frac{1}{4} ) + 1$

$= \frac{3}{4} - \frac{7}{4} + 1$

$= \frac{3 - 7 + 4}{4}$

$= 0$

1/4 is the zero of the polynomial

Answer 2

P(1/4)= 12/16-7/4+1
3/4-7/4+4/4
7/4-7/4 =0