Find p(-1) for the polynomial p(x)=x³-4x²+9x-5
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Answer:
Given,
p(x)=x^3-4x^2+9x-5
p(-1)=(-1)^3-4(-1)^2+9(-1)-5
p(-1)= -1-4-9-5
p(-1)= -5-5-9
p(-1)= -10-9
p(-1)= -19 (ANS)
I AM USING THE SYMBOL(^)TO REPRESENT THE POWERS OVER X
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