Question

find p(1) is p(x) =
${x}^{4} + 2 {x}^{4} + 4 {x}^{2} + 5x - 6$
​

Answer 1

p(x)=${x}^{4} + 2 {x}^{4} + 4 {x}^{2} + 5x - 6$

$p(1) = {1}^{4} + 2 \times {1}^{4} + 4 \times {1}^{2} + 5 \times 1 - 6$

$p(1) = 1 + 2 + 4 + 5 - 6$

$p(1) = 12 - 6$

$p(1) = 6$

Answer 2

$p(x) = {x}^{4} + 2 {x}^{2} + 4 {x}^{2} + 5x - 6 \\ p(1)= {1}^{4} + 2 ({1})^{4} + 4( {1})^{2}+ 5(1)- 6 \: \\ = 1 + 2 + 4 + 5 - 6 \\ = 12 - 6 \\ = 6 \\ p(1) = 6$Hσρє iт нєlρѕ υнн