Question

Find P(1),P(2) and P(4) for the p(x)=x²-5x+4​

Answer 1

Answer:

p(1) = 0

p(2) = -2

p(4) = 0

Step-by-step explanation:

Given,

P(x) = $x^{2}$ - 5x +4

p(1) = 1^2 -5*1+4=1-5+4=0

p(2) = 2^2-5*2+4=4-10+4=-2

p(4) = 4^2 -5*4 +4 = 16-20+4 = 0