Question

Find p(–1), p(y)=2Y2– 3y +8? Grade 9 NCERT​

Answer 1

Answer:

13

Step-by-step explanation:

p(y)=2$y^{2}$-3y+8

p(-1)=2($-1^{2}$)-3(-1)+8

     =2(1)-(-3)+8

     =2+3+8

     =13