Question

find p(-2) if p(t)=2+t+2t²-t³ please help me ​

Answer 1

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Answer 2

Answer:

BY PUTTING VALUE OF t

p(t) =2+t+2t^2-t^3

p(-2)=2+(-2)+2(-2)^2+(-2)^3

p(-2)=2-2+8-8

p(-2)=0