Find p(√2) if p(x) =x^2+√2x+1
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given p(X) = x²+√2x+1
p(√2) = (√2)²+√2*√2 +1
= 2+2+1 = 5
thus p(√2) = 5
p(√2) = (√2)²+√2*√2 +1
= 2+2+1 = 5
thus p(√2) = 5
Answered by
1
P(x)=x^2+√2x+1
P(√2)=√2^2+√2(√2)+1
P(√2)=2√2+4+1
=2√2+5
P(√2)=√2^2+√2(√2)+1
P(√2)=2√2+4+1
=2√2+5
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