find p(2) p (-2)of the polynomial p(x)= x square -6x+8
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It is given that p(x) = p(x) = x² - 6x + 8. To find a specific value of x, we substitute the value of x into the equation and solve the equation.
Given:
p(x) = x² - 6x + 8
Find the value of p(x) when x = 2:
p(x) = x² - 6x + 8
p(2) = (2)² - 6(2) + 8
p(2) = 4 - 12 + 8
p(2) = 0
Find the value of p(x) when x = -2:
p(x) = x² - 6x + 8
p(-2) = (-2)² - 6(-2) + 8
p(-2) = 4 + 12 + 8
p(-2) = 24
Answer: p(2) = 0 and p(-2) = 24
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