Question

Find p(a n b) when p(a) = 6/11 and p(b) = 5/11 and p( a U b) = 7/11

Answer 1

$<b>$
Hey there!


Solution:


Here P(A) = 6/11


P(B) = 5/11


P(A U B) = 7/11


Using Identitie:


P(A U B) = P(A) + P(B) - P(A ∩ B)


Using Values Acc. to question:


$\frac{ \textbf7}{ \textbf{11}} = \frac{ \textbf6}{ \textbf{11}} + \frac{ \textbf5}{ \textbf{11} }$ - P(A ∩ B)


$\frac{ \textbf7}{ \textbf{11}} = \frac{ \textbf{11}}{ \textbf{11}}$ - P(A ∩ B)


P(A ∩ B) = $1 - \frac{ \textbf7}{ \textbf{11}}$


P(A ∩ B) =$\frac{ \textbf4}{ \textbf{11}}$



#Be Brainly.

Answer 2

Here P(A) = 6/11

P(B) = 5/11

P(A U B) = 7/11

Using Identity:

P(A U B) = P(A) + P(B) - P(A ∩ B)

P(A U B) =4/11

Answer 3

Here P(A) = 6/11

P(B) = 5/11

P(A U B) = 7/11

Using Identity:

P(A U B) = P(A) + P(B) - P(A ∩ B)

P(A U B) =4/11