Math, asked by anshchakrabortp54gjx, 1 year ago

is this wrong? or right?.....

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Answered by siddhartharao77
4

Given : x = 7 + 4√3 and y = 7 - 4√3

Given : (1/x) + (1/y)

= > \frac{1}{7 + 4\sqrt{3}} * \frac{7 - 4\sqrt{3}}{7 - 4\sqrt{3}} + \frac{1}{7 - 4\sqrt{3}} * \frac{7 + 4\sqrt{3}}{7 + 4\sqrt{3}}

= > \frac{7 - 4\sqrt{3}}{(7)^2 - (4\sqrt{3})^2} + \frac{7 + 4\sqrt{3}}{(7)^2 - (4\sqrt{3})^2}

= > \frac{7 - 4\sqrt{3}}{49 - 48} + \frac{7 + 4\sqrt{3}}{49 - 48}

⇒ 7 - 4√3 + 7 + 4√3

⇒ 7 + 7

⇒ 14.


Therefore, the final answer is 14.


Hope this helps!


anshchakrabortp54gjx: thanks
siddhartharao77: welcome
Answered by Ashrealone
0

Answer:

Its right

Step-by-step explanation:

Mark me as the brainliest

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