Question

Find p and q, if (√(3 )-1)/(√3 +1 ) = p + q√3.

Answer 1

..........THANKU..........

Answer 2

Answer:

(root3-1)/(root3+1)=p+qroot3

Rationalise the denominator,

(root3-1)(root3-1)/(root3+1)(root3-1)=p+qroot3

(root3-1)^2/(root3^2 - 1^2)=p+qroot3

As we know (a-b)^2=(a^2-2ab+b^2)

[(root3)^2-2(root3x1)+1^2]/3-1=p+qroot3

(3-2root3+1)/2=p+qroot3

(4-2root3) / 2=p+qroot3

Take 2 as common,

2(2-root3)/2=p+qroot3

2-root3=p+qroot3

p+qroot3=2-root3

I am not sure what to do after this.