Find the roots of 9x² + 2x - 3 = 0
Answers
Answer:
(0 - 32x2) - 2x) - 3 = 0
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
-9x2 - 2x - 3 = -1 • (9x2 + 2x + 3)
Trying to factor by splitting the middle term
3.2 Factoring 9x2 + 2x + 3
The first term is, 9x2 its coefficient is 9 .
The middle term is, +2x its coefficient is 2 .
The last term, "the constant", is +3
Step-1 : Multiply the coefficient of the first term by the constant 9 • 3 = 27
Step-2 : Find two factors of 27 whose sum equals the coefficient of the middle term, which is 2 .
-27 + -1 = -28
-9 + -3 = -12
-3 + -9 = -12
-1 + -27 = -28
1 + 27 = 28
3 + 9 = 12
9 + 3 = 12
27 + 1 = 28
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step
3
:
-9x2 - 2x - 3 = 0
STEP
4
:
Parabola, Finding the Vertex
4.1 Find the Vertex of y = -9x2-2x-3
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens down and accordingly has a highest point (AKA absolute maximum) . We know this even before plotting "y" because the coefficient of the first term, -9 , is negative (smaller than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is -0.1111
Plugging into the parabola formula -0.1111 for x we can calculate the y -coordinate :
y = -9.0 * -0.11 * -0.11 - 2.0 * -0.11 - 3.0
or y = -2.889