find p and q where p and q a positive number the difference between P and Q is hundred and the sum of PQ is 540
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Let P be x
Then Q is = x+100
x+(x+100)=540
=) x+x+100=540
=) 2x = 540 - 100
=) 2x = 440
=) x = 440/2
=) x= 220
Thus P = 220
AND Q= 220 +100 =330
Then Q is = x+100
x+(x+100)=540
=) x+x+100=540
=) 2x = 540 - 100
=) 2x = 440
=) x = 440/2
=) x= 220
Thus P = 220
AND Q= 220 +100 =330
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