Find p, if quadratic equation py(y-2) + 6 = 0 has perfect square.
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Secondary School Math 5 points
Find value of p so that quadratic equation px(x-3)+9=0 has two equal roots
Ask for details Follow Report by Yuvrajshekhawat 03.11.2017
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somvanshi2132001
somvanshi2132001 Ambitious
Px(x-3) + 9 = 0
px2-3px+9=0
a=p , b=-3p , c=9
b2-4ac= (-3p)2-4(p)(9)
=9p2-36p
for having equal roots
b2-4ac = 9p2-36p = 0
9p2-36p = 0
9p(p-4) = 0
9p=0 (or) p-4=0
p=0(rejected) or p=4
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the value of y is 4
hope it helps
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