Find p
please explain step by step...
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Answered by
1
Answer:
P = 80
Step-by-step explanation:
sum of angles of quadrilateral is 360.
so A+B = 360-(110+50) = 200
both A and B are bisected, so
in triangle ABP,
A+B = 200/2 = 100
(it is not possible to find angles A and B individually)
sum of angles of triangle =180
so P = 180-(A+B) = 80
Answered by
1
Answer:
∠APB = 80°.
Step-by-step explanation:
here, ∠A + ∠B + ∠C + ∠D = 360° (Angle Sum Property of Quadrilateral)
= ∠A + ∠B + 50° + 110° = 360°
= ∠A + ∠B = 360° - 160°
= ∠A + ∠B = 200°
∵ ∠A and ∠B are bisected by AP and BP.
now, ∠APB + ∠PAB + ∠PBA = 180° (Angle Sum Property of Triangle)
= ∠APB + (∠A + ∠B)/2 = 180° ( we can write ∠PAB + ∠PBA as (∠A + ∠B)/2 )
= ∠APB = 180° - 100°
= ∠APB = 80°
∴∠APB = 80°
hope it will help you.
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