Question

Find P such that the point (P, 0) lies on the line joining the points (1,–1) and (3, 3)


please no spam​

Answer 1

$\underline{\textbf{Given:}}$

$\textsf{(P,0) lies on the line joining (1,-1) and (3,3)}$

$\underline{\textbf{To find:}}$

$\textsf{The value of P}$

$\underline{\textbf{Solution:}}$

$\underline{\textsf{Concept used:}}$

$\mathsf{The\;equation\;of\;line\;joining\;(x_1,y_1)\;and\;(x_2,y_2)\;is}$

$\boxed{\mathsf{\dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}}}$

$\textsf{The equation of the line joining (1,-1) and (3,3) is}$

$\mathsf{\dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}}$

$\mathsf{\dfrac{y+1}{3+1}=\dfrac{x-1}{3-1}}$

$\mathsf{\dfrac{y+1}{4}=\dfrac{x-1}{2}}$

$\mathsf{\dfrac{y+1}{2}=\dfrac{x-1}{1}}$

$\mathsf{y+1=2(x-1)}$

$\mathsf{y+1=2x-2}$

$\implies\mathsf{2x-y-3=0}$

$\textsf{Since (P,0) lies on the line 2x-y-3-0,}$

$\mathsf{2(P)-0-3=0}$

$\mathsf{2P=3}$

$\implies\boxed{\mathsf{P=\dfrac{3}{2}}}$

$\underline{\textbf{Find more:}}$

The equation of the line joining the origin to the point (-4,5)  

https://brainly.in/question/4743671