Question

Find pairs of natural numbers whose
least common multiple is 78 and the greatest divisor is 13

Answer 1

given- least common factor (LCM) = 78
 Greatest divisor is also a HCF = 13

As, we know ,    HCF x LCM = A x B ( A and B are two natural no. of which LCM and HCF is given)

Therefore, req product of no. = 13 x 78 = A x B =1014 or 2*3*13*13
since 13 is common in both no. as its hcf is 13
req no.= 13*3=39 and 13*2 = 26 
                                     

Answer 2

Step-by-step explanation:

78 and 13

HCF Multiply by LCM = sum of two numbers

13*78=A*B

13*13*3*2

HCF is 13