Question

FIND PERIMETER AND AREA OF RECTANGLE 8CM AND 5CM???

Answer 1

Perimeter of rectangle =2(l+b)

=2(8+5)cm=26cm.

New length =(8+x)cm.

New Breadth =(5+x)cm.

⇒2(13+2x)=52⇒13+2x=252=26.

⇒2x=13⇒x=213=6. 5cm.

Therefore New Length =(8+6. 5)cm =14. 5cm.

please mark as brilliant answer

Answer 2

$\underline\mathfrak{Question }$

FIND PERIMETER AND AREA OF RECTANGLE 8CM AND 5CM.

${{\ge{\tt{formulas \: used \: in \: the \: answer }}}} \\ \underline\mathfrak\pink{perimeter \: of \: a \: rectange = 2(l + b) } \\ \underline\mathfrak\blue{area \: of \: a \: rectange = l \times b } \\ \\ \underline\mathfrak{Answer}$

$length \: = 8 \: cm \\ breadth \: = 5 \: cm \\ \huge \fbox \orange{perimeter} \\ = 2(l + b) \\ = 2(8 + 5) \\ = 2(13) \\ = 26 \: cm \\ \\ \huge \fbox \orange{area} \\ = l \times b \\ = 8 \times 5 \\ = 40 \: cm$