Question

find perimeter of a rectangle of length is 5 2 by 3 and breadth is 7 5 by 2m.

Answer 1

2(l+b)
2(52/3+75/2)
2(104+105/2)=2(209/2)
=209
Hope this makes u understand

Answer 2

$perim \: of \: a \: rectangle = 2(l + b)$
$p = 2( \frac{52}{3} + \frac{75}{2} )$
$2( \frac{104 + 225}{6} )$
$2( \frac{329}{6} )$
$\frac{329}{3} = 109.67m$