Question

find perimeter of square of its diagonal is 10√2 m . ​

Answer 1

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Solution :

Let the side of the square = a

Diagonal ( d ) = 10√2

=> √2 a = 10√2

=> a = 10√2/√2

a = 10 cm ---( 1 )

Perimeter = 4a

P = 4 × 10

P = 40 cm

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Answer 2

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