find perimeter plzzzz
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length=24 cm, diagonal=25 therefore, by Pythagoras theorem l2 + b2 =d2 so, (24)2. +. b2 =(25)2 now,b2 =(25)2 - (24)2.
b2 = 625-576
b2=49
b=7
therefore perimeter of rect.= 2(l+b)
=2(24+7). =2×31. =62
b2 = 625-576
b2=49
b=7
therefore perimeter of rect.= 2(l+b)
=2(24+7). =2×31. =62
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