Find ph of 0.63 gram of hgno3 per 100 ml of solution is
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M=n/V
=w2/M2 x V
= 0.63x1000/63 mol-1L-1
=0.01 mol-1 [H+]
=[HNO3] =10-2 PH
= -log(H+)
= -log(10-2) =-(-2)log 10
PH=2
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