Chemistry, asked by ptasha106, 1 year ago

Find ph of 0.63 gram of hgno3 per 100 ml of solution is

Answers

Answered by payelMallik
0
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Answered by honey73840
0

M=n/V

=w2/M2 x V

= 0.63x1000/63 mol-1L-1

=0.01 mol-1 [H+]

=[HNO3] =10-2 PH

= -log(H+)

= -log(10-2) =-(-2)log 10

PH=2

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