Question

Find phthagorean triplet whose one member is 14

Answer 1

For any natural number m > 1, we have (2m) ² + (m2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

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Let  2 m = 14

 m = 7

 m² + 1 = 7²+ 1 = 49 + 1 = 50


m²- 1 = 7² - 1 = 49 - 1 = 48


check:

14² + 48² = 196 + 1304 = 2500 = 50²

Answer 2

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