Find phthagorean triplet whose one member is 14
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For any natural number m > 1, we have (2m) ² + (m2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.
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Let 2 m = 14
m = 7
m² + 1 = 7²+ 1 = 49 + 1 = 50
m²- 1 = 7² - 1 = 49 - 1 = 48
check:
14² + 48² = 196 + 1304 = 2500 = 50²
=========================================================
Let 2 m = 14
m = 7
m² + 1 = 7²+ 1 = 49 + 1 = 50
m²- 1 = 7² - 1 = 49 - 1 = 48
check:
14² + 48² = 196 + 1304 = 2500 = 50²
anesha633:
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