Find point on 2x+3y=6 which is closest to the origin
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Answer:
Step-by-step explanation:
(0, 0) (x,y) where y = 2x + -3
(0,0) (x, 2x+ -3)
Now you have to use the distance formula:
D= √(x² +y²)
D= √(x² + (2x+ -3)²)
D=√ (x² + 4x² + -12x +9)
D=√(5x² + -12x + 9)
Now you have to take the derivative and set it to 0.
D'= 10x+ -12 / 2√(5x² + -12x + 9) = 0
D' = 5x + -6 / √(5x² + -12x + 9) = 0
Since we only need to numerator to = 0 for the whole thing to be 0 we do the following: 5x + -6= 0
Solve for x
5x = 6
x = 5/6
Now we need to find y:
y=2x+ -3
y=2(5/6) + -3
y= -4/3
Answer: (5/6 , -4/3)
Hope that was helpful!
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