find point on x-axis which air distance of 5 units from the point 5 and - 4
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Answer:
On X axis Y=0 .....(I)
applying distance Formula
√(5-x)^2+(-4+0)^2=5
25+x^2-10x+16=25
x^2-10x+16=0
(x-8)(x-2)=0
X=8 or 2
The points are
(8,0) and (2,0)
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