Question

Find the equation of the circle whose centre is (2,-3) and radius is 5

Answer 1

Answer:

Hey mate here is your answer.....

(x-2)²+(y+3)² = 5²

x²+4-4x+y²+9+6y = 25

x²+y²-4x+6y+13 = 25

x²+y²-4x+6y-12 = 0

Hope it helps you....

Answer 2

Answer:

x²+y²-4x+6y-12=0

Step-by-step explanation:

Equation of a circle : (x-a)²+(y-b)² = r²

Here,

(x-2)²+(y+3)²=5²

x²+4-4x + y²+9+6y = 25

x²+y²-4x+6y-12=0

Hope it helps.