Question

find points of y axis which lies on the locus represented by equation 3x^2-5xy+6y^2=54=0

Answer 1

Answer:

The required points on y axis are

(0, 3) and (0, -3)

Step-by-step explanation:

Concept used:

Equation of y axis is x=0

Given equation is

$3x^2-5xy+6y^2-54=0$

put x=0, we get

$3x^2-5xy+6y^2-54=0$

$3(0)^2-5(0)y+6y^2-54=0$

$6y^2-54=0$

$y^2-9=0$

$y^2=9$

y = ±3

The required points on y axis are

(0, 3) and (0, -3)