Question

Find points on the x aixis which are at a distance of 5 units from the point (5,-4)​

Answer 1

Answer:

Let the point on x.axis be (k,0)

Now using distance formula we have

Using distance formula we have

(k−5)

2

+(0+4)

2

=5

(k−5)

2

+16

=5

squaring both sides,we have

(k−5)

2

+16=25

(k−5)

2

=9

∴k=8,2

Point is (2,0),(8,0)