Question

Find points on the x-axis, each of which is at a distance of 10 units from
the point A(11,-8).​

Answer 1

Step-by-step explanation:

let the point on x- axis is (x,0)

as y-coordinate on x axis is 0

given point is A(11,-8)

distance formula= √((x2-x1)^2+(y2-y1)^2) sq units

=√(11-x)^2+(8-0)^2= 10 unis

(11-x)^2+64 is 10^2

(11-x)^2is 100-64 so

(11-x)is 6 and x is 5

so the point on x - axis is (5,0)