Question

find potential difference at the center of diapole . Mathematically ??? Plz reply quickly ..​

Answer 1

Explanation:

I thought the electric potential at point B would be positive because placing a positive charge at point B would cause it to move releasing energy while doing so. The answer key states that the electric potential is 0 at point B and while the math seems to support that because kQr+k−Qr=0, I don't understand conceptually how the potential is 0.

Answer 2

In a uniform electric field, the equation to calculate the electric potential difference is super easy: V = Ed. In this equation, V is the potential difference in volts, E is the electric field strength (in newtons per coulomb), and d is the distance between the two points (in meters)

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