Question

if the zeros of the polynomial x^3-14x^2+37x-60 are alpha. beta, gamma then find a)alpha+beta+gamma b)alpha beta+ beta gamma+ gamma alpha c)alpha beta gamma

Answer 1

Answer:

sum of zeros = -b/a

-(-14)/1=14

sum of product of two zeroes =c/a

37

product of zeros -d/a=-(-60)=60

Answer 2

Answer:

As per question,

a=1,b= -14,c=37,d= -60

We know,

Alpha +beta+gamma= -b/a

= -(-14)/1 =14/1 =14

Alpha beta+beta gamma +gamma alpha=c/a

=37/1 =37

Alpha beta gamma= -d/a =-(-60)/1 =60