Question

find pqh of this

help me please​

Answer 1

Answer:

Step-by-step explanation:

AB || CD and EF intersector => <EGB = <GHD = 35 °

<GHD = vert opp. <QHP = 35 °

=> from triangle PQH we get <PQH=180 °-(<QPH + <QHP)

                                                          =180 °-(90 °+ 35 °)=180 °- 125 °= 55 °