Question

Find pressure exerted by 76m mercury column at bottom point. (Given that- density of mercury is 13600 kg/m^3)

Answer 1

you already know,
$pressure = density \times g \times h$
where g is acceleration due to gravity and h is height of mercury column.

So given,h=76 meter
density=13600kg/m^3
and you know g=9.8 m/s^2
$so \: pressure = 13600 \times 76 \times 9.8$
pressure=10,129,280kg/m/s^2 or 10.1×10^6 Pascal.

Thanks.
Tripathy.