find principal values of the cot-¹(✓3)
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Let cot-1√3 = ∅ then cot ∅ = √3 = cot ( π /6 ). We know that the range of the principal value branch of cot−¹ is (0, π) and cot ( π /6 ) = √3. Therefore, the principal value of cot-1√3 is π /6.
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Let cot-1√3 = ∅ then cot ∅ = √3 = cot ( π /6 ). We know that the range of the principal value branch of cot−¹ is (0, π) and cot ( π /6 ) = √3. Therefore, the principal value of cot-1√3 is π /6 .
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