Find Prove that (secA+tanA-1) (secA-tanA+1)=2 tanA?
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In (secA + tanA - 1) (secA - tanA + 1) = 2 tanA
Taking LHS
=(secA + tanA - 1) (secA - tanA + 1)
=sec²A - tanAsecA + secA + tanAsecA - tan²A + tanA -secA + tanA -1
= 1-1 +2tanA (as sec²A - tan²A = 1)
= 2tanA
HENCE PROVED
:) Hope this helps !!!
Taking LHS
=(secA + tanA - 1) (secA - tanA + 1)
=sec²A - tanAsecA + secA + tanAsecA - tan²A + tanA -secA + tanA -1
= 1-1 +2tanA (as sec²A - tan²A = 1)
= 2tanA
HENCE PROVED
:) Hope this helps !!!
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