find Pythagorean triplet whose one member is n=5
Answers
Answer:
5, 12,13
Step-by-step explanation:
as the number 5 is odd,
the triplets are n , (n²+1)/2 , (n²-1)/2
= 5 , (5²+1)/2 , (5²-1)/2
= 5 , 13 , 12
PROVE -
5² + 12² = 25 + 144 = 169 = 13²
Given : Pythagorean Triplet whose one number is 5.
To Find : Pythagorean Triplet
Solution:
A Pythagorean triplet ( a , b , c)
where c² = a² + b² , c > a , b
a , b and c are the sides of a right angle triangle where c is the hypotenuse
a Pythagorean Triplet whose smallest number is 5.
is ( 5 , 12 , 13)
5² = 25
12² = 144
13² = 169
25 + 144 = 169
5² +12² = 13²
( 5 , 12 , 13) is a a Pythagorean Triplet whose smallest number is 5.
other possible is
(3 , 4 , 5)
3² + 4² = 5²
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