Question

find quadrastic polynomial if zeros are -3/2 and 1/3​

Answer 1

6x² + 7 - 3

Step-by-step explanation:

sum of zeroes = -b/a

$\frac{ - 3}{2} + \frac{1}{3} = \frac{ - b}{a}$

$\frac{( - 3)3 + 2}{6} = \frac{ - b}{a}$

$\frac{( - 9) + 2}{6} = \frac{ - b}{a}$

-7/6. = -b/a

product of zeroes = c/a

$\frac{ - 3}{2} \times \frac{1}{3} = \frac{c}{a}$

-3/6 = c/a

now ,

x² - (sum of zeroes)x + product of zeroes.

x² - (-7/6) + (-3/6)

6x² + 7 - 3