Find quadratic equation whose two zeros 7+ root 5 and 7- root 5
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Answer:
x^2+14x+44
Step-by-step explanation:
sum of zeros=7+root5+7-root5
=7+7=14
Product of zeros=(7+root5)(7-root5) =49-5 =44
Required polynomial
x^2--sum of zeros
X--product of zeros
Then, the quadratic equation is x^2+14x+44
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